Theoretical Yield Calculator
This theoretical yield calculator will answer all the burning questions you have regarding how to calculate the theoretical yield, such as how to find theoretical yield as well as the theoretical yield definition and the theoretical yield formula. Before carrying out any kind of lab work you need to work out what is the theoretical yield, so you know how much of your product, be it a molecule or lattice, you can expect from a given amount of starting material. This allows you to work out how efficiently you carried out your reaction (the quantity you can find at the actual yield calculator), which is done by . The theoretical yield equation can also be used to ensure that you react equal moles of your reactants, so no molecule is wasted.
We also have a [percent yield calculator] to assist you with your calculations.
IMPORTANT NOTE: Yields can only be found using the limiting reagent. If you are uncertain which of your reagents are limiting, plug in your reagents one at a time, and whichever one gives you the lowest mole is the limiting reagent. Remember to hit refresh at the bottom of the calculator to reset it.
Theoretical yield definition
What is theoretical yield? It is the amount of a product that would be formed if your reaction was 100% efficient. How to achieve 100% efficiency? Well, it would mean that every molecule reacted correctly (i.e., no side products are formed) at every step and that no molecule was lost on the sides of the glassware. As a normal reaction deals with quintillions of molecules or atoms, it should be obvious that some of these molecules will be lost. Therefore the percent yield will never be 100%, but it is still useful to know as a metric to base your efficiency of reaction off. For more on this check out our percent yield calculator (link above). Find out how to calculate theoretical yield with the theoretical yield equation below!
Theoretical yield formula
Using the theoretical yield equation helps you in finding the theoretical yield from the mole of the limiting reagent, assuming 100% efficiency. So, to stop you from wondering how to find theoretical yield, here is the theoretical yield formula:
Where:
 $m_{\text{mol},\text{product}}$ — The molecular weight of the desired product;
 $m_{\text{lim}}$ — The mass of the limiting reagent; and
 $c_{\text{lim}}$ — The stoichiometry of the limiting reagent.
The number of moles of the limiting reagent in the reaction is equal to:
Where:
 $m_{\text{mol},\text{lim}}$ — The molecular weight of the limiting reagent;
 $n_{\text{lim}}$ — The number of moles of the limiting reagent; and
 $c$ — The stoichiometry of the desired product.
Stoichiometry is defined as the number before the chemical formula in a balanced reaction. If no number is present, then the stoichiometry is 1. The stoichiometry is needed to reflect the ratios of molecules that come together to form a product. The good thing about this calculator is that it can be used any way you like, that is to find the mass of reactants needed to produce a certain mass of your product. All this information is hidden in the moles, which can be derived from a solution's molarity or concentration (you can learn how to do so with our molarity calculator and concentration calculator).
How to calculate theoretical yield?
Now, the theoretical yield formula may seem difficult to understand so we will show you a quick guide on how to calculate the theoretical yield. The measurements you need are the mass of the reagents, their molecular weights, the stoichiometry of the reaction (found from the balanced equation), and the molecular weight of the desired product. Look no further to know how to find the theoretical yield:
 First, calculate the moles of your limiting reagent. This is done by using the second equation in the theoretical yield formula section (pro tip: make sure that the units of weight are the same for the correct results: you can use the weight converter if you need help with the factors).
 Select the reactant that has the lowest number of moles when stoichiometry is taken into account. This is your limiting reagent. If both have the same amount of moles, you can use either.
 Use the first equation to find the mass of your desired product in whatever units your reactants were in.
There you go! If you are still struggling, check the examples below for a more practical approach.
Examples of yield calculations
Time for some examples. Let's say you are doing a nucleophilic addition reaction, forming hydroxyacetonitrile from sodium cyanide and acetone.
Let's ignore the solvents underneath the arrow (they will both be present in excess and therefore will not be limiting reagents), but also the sodium cation of the sodium cyanide, as it is just a spectator ion. If we react 5\ \text{g}} of acetone with $2\ \text{g}$ of cyanide, what is the theoretical yield of hydroxyacetonitrile?

We need to work out the limiting reagent first. As the stoichiometry of both reagents is 1 (i.e., one molecule of acetone reacts with one molecule of cyanide), we can simply use the
mass = molecular weight × mole
equation to find this: Let's rearrange the equation to find moles. This gives:
$\text{mole} = \text{mass}/\text{molecular weight}$  Acetone has a molecular weight of $58\ \text{g}/\text{mole}$, so:
$\text{mole} = 5 / 58 = 0.862\ \text{mol}$  Cyanide has a molecular weight of $26\ \text{g}/\text{mole}$, so:
$\text{mole} = 2 / 26 = 0.0769\ \text{mol}$  So there are fewer moles of cyanide, meaning this is the limiting reagent.
 Let's rearrange the equation to find moles. This gives:

Knowing the limiting reagent and its moles means that we know how many moles of the product will form. As the stoichiometry of the product is $1$, $0.0769$ moles will form.

We can once again use the $\text{mass} = \text{molecular weight} \times \text{mole}$ equation to determine the theoretical mass of the product. The molecular weight of hydroxyacetonitrile is $85\ \text{g}/\text{mol}$:
Now we know that if we carry out the experiment, we would expect $6.54\ \text{g}$ of hydroxyacetonitrile. Not too bad right!
Let's say you are trying to synthesize acetone to use in the above reaction.
You react $8\ \text{g}$ of calcium carbonate ($100\ \text{g}/\text{mol}$) with $9\ \text{g}$ of acetic acid ($60\ \text{g}/\text{mol}$), how much acetone is formed?

Once again, we need to work out which is the limiting reagent first. Let's use the $\text{mass} = \text{molecular weight}\cdot \text{mole}$ equation again:
 Let's rearrange the equation to find moles. This gives:
$\text{mole} = \text{mass} / \text{molecular weight}$  Lets find the moles of acetic acid:
$\text{mole} = 9 / 60 = 0.15\ \text{mol}$  And the moles of calcium carbonate:
$\text{mole} = 8 / 100 = 0.08\ \text{mol}$  It looks like calcium carbonate is the limiting reagent. But wait! We haven't considered the stoichiometry. Since we need 2 molecules of acetic acid to form one molecule of acetone, we need to divide the moles of acetic acid by $2$:
$\text{mole} = 0.15 / 2 = 0.075\ \text{mol}$  So it turns out that the acetic acid is the limiting reagent!
 Let's rearrange the equation to find moles. This gives:

Now that we know the limiting reagent and its moles, we know how many moles of the product will form. As the stoichiometry of the product is $1$, $0.75$ moles will form.

Use the $\text{mass} = \text{molecular weight}\cdot\text{mole}$ equation to determine the theoretical mass of the product. The molecular weight of acetone is $58\ \text{g}/\text{mol}$:
$\text{mass} = 58 × 0.075 = 4.35\ \text{g}$
So from this reaction, we should get, theoretically speaking, $4.35\ \text{g}$ of acetone. Nice!
Now go on and conquer the world of theoretical yield calculations, you can do it!
FAQ
How do I find theoretical yield?
To find the theoretical yield:
 Balance the reaction.
 Identify the limiting reagent, which is the reagent with the fewest moles.
 Divide the fewest number of reagent moles by the stoichiometry of the product.
 Multiply the result of Step 3 by the molecular weight of the desired product.
What is theoretical yield?
The theoretical yield is the amount of product that would be formed from a reaction if it was 100% efficient. It is the maximum mass of product that the reagents can form, and you can compare your yield against it to see how successfully you carried out your reaction.
Is the limiting reactant the theoretical yield?
No, the limiting reactant is not the theoretical yield. To find the theoretical yield, you must find the number of moles present of the limiting reagent. You can then multiply this number by the stoichiometry of the desired product to find the number of moles formed, then use this to derive the theoretical yield.
What is the theoretical yield of carbon dioxide?
The theoretical yield of CO_{2} depends on the reaction taking place and the amount of reagents. To find the theoretical yield, you can follow the steps below:
 Find the moles of the limiting reagent.
 Multiply the moles of the limiting reagent by the stoichiometry of carbon dioxide in the reaction to give the moles of CO_{2} produced.
 Multiply the moles of CO_{2} produced by 44, the molecular weight of CO_{2}, to get the theoretical yield of your reaction.