If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A

Advertisement Remove all ads

#### Solution

tan 2A = cot (A – 18°)

cot (90° – 2A) = cot (A – 18°)

(∵ cot (90° – θ) = tan θ)

90° – 2A = A – 18°

3A = 108°

A = 36°

Concept: Trigonometric Ratios of Complementary Angles

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads