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Normality vs. Molarity: What's the Difference?

Let's dive into the fascinating world of chemistry to explore two key concepts: normality vs. molarity. These two terms are often used to express the concentration of solutions, but be careful; they do not mean the same thing. So, what exactly is the difference between normality and molarity, and more importantly, when should they be used?

By the end of this article, you'll have all the keys to distinguish between them easily. Ready to find out? Let's go!

What is molarity?

Molarity, also known as the molar concentration of a solute, is defined by the number of moles of solute present in 1 liter of solution. Molarity is expressed as mol/L{\text{mol}}/{\text{L}}, abbreviated as M\text{M} (pronounced “molar”).

The molarity formula is simple:

Molarity (M)=nsoluteVsolution=msoluteWsolute×Vsolution\begin{align*} \mathrm{Molarity\ (M)} &= \mathrm{\frac{n_{solute}}{V_{solution}}}\\[1.2em] & = \mathrm{\frac{m_{solute}}{W_{solute} \times V_{solution}}} \end{align*}

where:

  • M\text{M} — Molarity or molar concentration (in moles per liter, mol/L);
  • nsolute\mathrm{n_{solute}} — Amount of solute (in moles);
  • Vsolution\mathrm{V_{solution}} — Volume of solution (in liters);
  • msolute\mathrm{m_{solute}} — Mass of solute (in grams); and
  • Wsolute\mathrm{W_{solute}} — Molar mass 🇺🇸 of solute (in g/mol).

For example, if you dissolve 2 moles of salt in 1 liter of water, the molarity of the solution is 2 mol/L or 2M (2 molar). Want to calculate molarity in a flash? Use our molarity calculator 🇺🇸!

Molarity is widely used in chemistry because it is simple, direct, and universal. Let's now move on to normality.

What is normality?

Normality, denoted by N\text{N}, otherwise known as the normal concentration, is a measure of concentration of solute in gram equivalents per volume of the solution. For a solution with "x" grams of solute, the normality equation is:

Normality (N)=msoluteEWsolute×Vsolution\mathrm{Normality\ (N)} = \mathrm{\frac{m_ {solute}}{EW_{solute} \times V_{solution}}}

where:

  • N\text{N} — Normality (in eq/L);
  • msolute\mathrm{m_{solute}} — Mass of solute (in grams);
  • EWsolute\mathrm{{EW}_{solute}} — Equivalent weight of solute; and
  • Vsolution\mathrm{V_{solution}} — Volume of solution (in liters).

Equivalent weight (more precisely, equivalent mass) is the mass of one equivalent, that is, the mass of a given substance which will combine with or displace a fixed quantity of another substance. It's given by:

EWsolute=Wsoluten\mathrm{{EW}_{solute}} = \frac{\mathrm{W_{solute}}}{n}

where:

  • Wsolute\mathrm{W_{solute}} — Molar mass of the solute (in g/mol); and
  • nn — Valence factor, i.e., number of equivalents per mole (in eq/mol). It's reaction-dependent (e.g., number of H⁺ ions released, OH⁻ ions accepted, or electrons transferred).

💡 The equivalent weight is determined by the amount of an ion that reacts, which could change depending on the reaction:

  • In acid-base chemistry, normality expresses the concentration of protons (H+) or hydroxide ions (OH−) in a solution.
  • In redox reactions, the valence factor describes the number of electrons an oxidizing/reducing agent can accept/donate.
  • In precipitation reactions, the valence factor measures the number of ions precipitating in a given reaction.

For example, for acids, the valence corresponds to the number of H+ ions it can release. Take sulfuric acid H2SO4, for example. Each H2SO4 molecule can release two H+ ions in water, so its valence is 2.

Normality is essentially molarity multiplied by the valence factor (nn). Check out our normality calculator 🇺🇸 to know more about it!

N=M×n\mathrm{N = M} \times n

To illustrate further, the molarity and normality of some acids and bases are given below:

Molar mass, equivalent weight, and molarity-normality relationship for common acids and bases

Acid/Base

W (g/mol)

EW (g/eq)

M vs. N

HCl

36.5

36.5

1M = 1N

H2SO4

98

98/2 = 49

1M = 2N

NaOH

40

40

1M = 1N

Ca(OH)2

74

74/2= 37

1M = 2N

💡 H2SO4 and Ca(OH)2 each have n=2n=2 because they can release or react with two reactive units per molecule (two H⁺ ions for sulfuric acid and two OH⁻ ions for calcium hydroxide).

The table below highlights the main differences between normality and molarity:

Normality vs. Molarity comparison table

Feature

Normality (N)

Molarity (M)

Definition

Gram equivalents of solute per liter of solution

Moles of solute per liter of solution

Units

eq/L

mol/L

Depends on reaction

Yes

No

Temperature sensitivity

Yes, volume changes with temperature

Yes, also volume-based, so affected by temperature

Use cases

Acid-base titrations, redox reactions, and precipitation reactions

General concentration reporting, stoichiometry, and preparing standard

Curious about how molarity compares to molality instead? Check out our Molarity vs. Molality: Understanding the Key Differences for another side-by-side comparison.

To make the normality vs. molarity concept more concrete, let’s examine three practical examples: one for calculating molarity, one for calculating normality, and one for converting between molarity and normality.

Example #1: Calculating molarity

Problem:
You dissolve 10 g of NaOH (molar mass of 40.0 g/mol) in enough water to obtain 500 mL of solution. What is the molarity?

Solution:

  1. Calculate the number of moles of solute:
10 g40.0 g/mol=0.25 mol\mathrm{\frac{10\ g}{40.0\ g/mol} = 0.25 mol}

This gives 0.25 moles of solutes.

  1. Convert the volume to liters:
500 mL=0.500 L\mathrm{500\ mL = 0.500 L}
  1. Substitute the values into the molarity formula:
M=0.25 mol0.500 L=0.50 mol/L\mathrm{M = \frac{0.25\ mol}{0.500\ L} = 0.50 mol/L}

Answer:
The molarity of the NaOH solution is 0.50 mol/L\mathrm{0.50 mol/L}.

Example #2: Calculating normality

Problem:
You dissolve 4.9 g of H2SO4 (molar mass of 98.0 g/mol) in enough water to obtain 250 mL of solution. What is the normality for an acid-base reaction in which H₂SO₄ donates 2 H⁺ ions?

Solution:

  1. Find the equivalent weight:
98.0 g/mol2 eq/mol=49.0 g/eq\mathrm{\frac{98.0\ g/mol}{2\ eq/mol} = 49.0\ g/eq}
  1. Convert the volume to liters:
250 mL=0.250 L\mathrm{250\ mL = 0.250 L}

To simplify your volume conversion, don't hesitate to use our volume converter 🇺🇸.

  1. Apply the normality formula:
N=4.9 g49.0 g/eq×0.250 L=0.40 eq/L\mathrm{N} = \mathrm{\frac{4.9\ g}{49.0\ g/eq \times 0.250\ L} = 0.40\ eq/L}

Answer:
The normality of the H2SO4 solution is 0.40 eq/L\mathrm{0.40 eq/L}.

Example #3: Converting between molarity and normality

Problem:
A solution of H2SO4 has a molarity of 1.5 M. What is its normality for complete acid-base dissociation?

Solution:

  1. Identify the valence factor. We know that H2SO4 releases 2 H+ ions, so n=2n=2.
  2. Apply the molarity to normality formula:
1.5 M×2=3.0 N\mathrm{1.5\ M \times 2 = 3.0\ N }

Answer:
A 1.5 M H2O4 solution is 3.0 N\mathrm{3.0\ N} in this reaction.

What you should remember from this normality vs. molarity comparison is that, while molarity indicates the number of moles of solute present in a liter of solution, normality focuses on the number of reactive equivalents per liter, which depends on the type of reaction. It's important that you know the difference between normal vs. molar concentrations in order to choose the appropriate measurement for your work.

No. 1M is equivalent to 1N only if the n-factor (or valence factor) equals 1. Their molarity and normality will not be equal for compounds with an n-factor other than 1.

1N NaOH means 1 equivalent of NaOH in 1 liter of water, and 1M NaOH means 1 mole of NaOH in 1 liter of water.

Suppose you know the molarity of an acid or base solution. In that case, you can easily convert it to normality by multiplying the molarity by the number of hydrogen (or hydroxide) ions present in the acid (or base).

Normality is expressed in equivalents per liter (eq/L). Equivalents (eq) represent the amount of substance that reacts with or provides one mole of a reactive species (H+ ions, OH- ions, electrons, etc.). The “per liter” (L) indicates the volume of the entire solution, just as in molarity.

This article was written by Claudia Herambourg and reviewed by Steven Wooding.