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Law of Sines: The Ambiguous Case

This article will teach you how to use the law of sines to solve ambiguous SSA (side-side-angle) cases. But before, let's start by recalling the law of sines. The law of sines applies to any triangle, equating the ratios of the sines of the angles to the lengths of the corresponding sides.

asinα=bsinβ=csinγ\frac{a}{\sin \alpha} = \frac{b}{\sin \beta} = \frac{c}{\sin \gamma}

If you want to know more about the law of sines, check out our detailed article: What is the Law of Sines? (Sine Rule Explained).

In short, we can use the law of sines to find unknown angles and lengths in triangles where we know either two lengths and an opposite angle, or two angles and an opposite side.

🙋 If you want to explore the formula directly, try our law of sines calculator 🇺🇸.

Using the law of sines to determine an unknown side or angle can result in an ambiguous answer. The ambiguous case of the sine rule occurs under the following conditions:

  • You only know the angle α\alpha and sides aa and cc;
  • The angle αα is acute (α<90α \lt 90^\circ);
  • aa is shorter than cc (a<ca \lt c); and
  • aa is longer than the altitude hh from angle β\beta, where h=c×sinαh = c \times \sin \alpha (or a<c×sinαa \lt c \times \sin \alpha).

This situation leads to two possible solutions because the same sine value corresponds to two different angles: θ\theta and 180θ180^\circ - \theta.

It is important to note that the law of sines and the ambiguous case can only occur if we are given the lengths of two sides and an opposite angle; however, depending on the values, there are three possibilities to distinguish in this case: no triangle exists, one triangle exists, or two triangles exist.

We have summarized the possible cases when two sides aa and bb, and an opposite angle α\alpha are known in the table below.

Law of sine and ambiguous case table.

Case

If α\alpha is acute

If α\alpha is obtuse

a<ha \lt h

No triangle exists

No triangle exists

a=ha = h

One triangle exists

a>ba \gt b

One triangle exists

One triangle exists

h<a<bh \lt a \lt b

Two triangles exist

a=ba = b

No triangle exists

💡 Check out our Pythagorean theorem 🇺🇸 to learn more about triangles!

Suppose you have a triangle ABCABC with a=3 ina = 3 \ \text{in}, b=9 inb = 9 \ \text{in}, α=10\alpha = 10^\circ. Let's determine all possible measures of β\beta (to the nearest degree).

  1. Check how many triangles are possible. Since α\alpha is acute, we calculate the altitude:
h=b×sinα=9 in×sin(10)1.56 in \begin{align*} h &= b \times \sin \alpha = 9 \ \text{in} \times \sin(10^\circ) \\ &\approx 1.56 \ \text{in}\ \end{align*}

Because h<a<bh < a < b, it is possible to build two different triangles.

  1. Apply the law of sines 🇺🇸:
sinβb=sinαasinβ9 in=sin(10)3 insinβ=sin(10)3×9 insinβ0.521\begin{align*} \frac{\sin \beta}{b} &= \frac{\sin \alpha}{a}\\[1.2em] \frac{\sin \beta}{9\ \text{in}} &= \frac{\sin(10^\circ)}{3\ \text{in}}\\[1.2em] \sin \beta &= \frac{\sin(10^\circ)}{3} \times 9\ \text{in}\\[1.2em] \sin \beta &\approx 0.521 \end{align*}
  1. Solve for β\beta:
β=sin1(0.521)β31.4\begin{align*} \beta &= \sin^{-1}(0.521)\\[.2em] \beta &\approx 31.4^\circ \end{align*}
  1. Since sin(θ)\sin(\theta) has the same value for θ\theta and 180θ180^\circ - \theta, there is another possible solution:
β=18031.4=148.6 \beta = 180^\circ - 31.4^\circ = 148.6^\circ
  1. Check if the triangle angle sum is less than 180180^\circ:
α+β=10+148.6=158.6<180\alpha + \beta = 10^\circ + 148.6^\circ = 158.6^\circ < 180^\circ

So this value of β\beta is also possible.

There are two possible measures for β\beta: β31.4\beta \approx 31.4^\circ or β148.6\beta\approx 148.6^\circ. Hence, two distinct triangles can be formed.

🙋 Interested in geometry in general? Try our triangle area calculator 🇺🇸.

The ambiguous case of the sine rule occurs in the SSA configuration, when two sides and a non-included angle are given. In this situation, the law of sines may produce two triangles, one triangle, or no triangle at all. Knowing how to test for acute and obtuse angles allows you to interpret the results correctly.

Because the sine of an angle and its supplement are equal, i.e., sin(θ) = sin(180° − θ). This means that when solving for an angle with the sine rule, both an acute and an obtuse angle might satisfy the equation.

The ambiguous case of the sine rule occurs only in the SSA configuration when two sides and a non-included angle are known. It does not appear in the ASA, AAS, SAS, or SSS cases.

No. In right triangles, the sine rule gives a unique solution, because the right angle eliminates the possibility of an obtuse solution. The ambiguous case only arises in oblique (non-right) triangles.

This article was written by Claudia Herambourg and reviewed by Steven Wooding.