Adding and Subtracting Polynomials Calculator
Welcome to Omni's adding and subtracting polynomials calculator, where we'll learn to find the sum and difference of polynomials. In fact, the operation is fairly simple, much simpler than polynomial multiplication. Nevertheless, let's go through it slowly, step by step, to get a clear understanding of the process. And once we know how to add polynomials and how to subtract polynomials, we'll go through a nice example at the end.
Polynomials, monomials, binomials
Ever since we've gone past the point of counting apples and candies, we've been handling polynomials without even knowing it. The moment we first met geometry and laid our eyes on the formula for the area of a square, our world changed and would never go back to what it had been. After all, mathematics decided to get letters involved.
In algebra, those letters are known as variables. They represent an object (usually a number) that we don't know or don't want to specify at that moment. They are especially useful in formulas that describe laws that govern our world and the dependence between different values. For instance, the equation
A = πr² uses variables
π, where only
π is determined beforehand. The other two represent not a specific number but a universal quantity: the area of a circle and the length of its radius, respectively.
A polynomial is an algebraic expression (not an equation, mind you!) in which the variables appear only in non-negative integer powers. In other words, the quantity cannot contain things like radicals, logarithms, or trigonometric functions with letters inside them. Below we list a few examples of polynomials:
x + 2y
a² + 2ab + b
n³ - 0.7n + ⅜
1 + 3 + x⁵ - x⁷ + 19x⁵
Binomials and monomials are special cases of polynomials: they are those with two and one terms, respectively (as suggested by the prefixes bi- and mono- meaning double and single). As such, the first of the above is an example of a binomial, while the third is a monomial. There are also trinomials, which have (surprise, surprise!) three terms, but they're not nearly as common as the other two and appear mostly in quadratic equations.
Now that we know what objects we're dealing with, it's time to get down to business and introduce some operations. First of all, we'll see how to add polynomials.
How to add polynomials?
Just like in arithmetics, finding the sum in the new setting is a fairly easy task. If we were to, say, divide polynomials, the matter would get significantly harder. However, we can enjoy the simplicity of addition and even make the task extra simple with our adding polynomials calculator.
The basic rule on how to add polynomials is: combine only similar terms. To make it more mathematically precise, we can only add monomials with the same variables and variable powers (but possibly, different constants before them). For instance, we can add
-0.5xy², but not to
2x²y² since the power of
x is different (
2 instead of
1). Not to mention terms that have different letters: you can never group those into one.
Let us mention here that our adding and subtracting polynomials calculator deals only with expressions that have one variable (in our tool, it's
x) and at most in power
6. Such objects are most common in algebra, and they're enough to explain the concept.
Suppose that we have two such polynomials
P(x) = a₅x⁵ + a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀ and
Q(x) = b₄x⁴ + b₃x³ + b₂x² + b₁x + b₀ and you want to add them. Note how their degrees (the maximal powers of
4, respectively. So what is the sum of the polynomials?
As mentioned above, we can add only terms that have the same powers of the variable, which means that, for instance, we combine
b₃x³ and nothing else. And the combining means simply adding the numbers in front:
P(x) + Q(x) = (a₅x⁵ + a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀) + (b₄x⁴ + b₃x³ + b₂x² + b₁x + b₀)
= a₅x⁵ + (a₄ + b₄)x⁴ + (a₃ + b₃)x³ + (a₂ + b₂)x² + (a₁ + b₁)x + (a₀ + b₀).
Observe how the first summand has only
a₅ in front since there was no term with
And that's all there is. Easy, wasn't it? And we can always count on Omni's adding polynomials calculator to do it all for us.
How to subtract polynomials?
Subtracting polynomials is to adding polynomials what subtracting numbers is to adding numbers. Well, that sentence didn't clarify much, did it? Let's try to phrase it differently.
Subtracting polynomials is as easy as adding them; we simply change sums to differences throughout. To illustrate this, let's see how to subtract polynomials
P(x) = a₅x⁵ + a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀ and
Q(x) = b₄x⁴ + b₃x³ + b₂x² + b₁x + b₀. The rule is the same as in the above section: we're only allowed to combine alike terms. And combining means finding the difference of the coefficients:
P(x) - Q(x) = (a₅x⁵ + a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀) - (b₄x⁴ + b₃x³ + b₂x² + b₁x + b₀)
= a₅x⁵ + (a₄ - b₄)x⁴ + (a₃ - b₃)x³ + (a₂ - b₂)x² + (a₁ - b₁)x + (a₀ - b₀).
The formula looks the same, but we need to be careful with the signs. Addition is commutative, so it didn't matter much in which order we put the summands (after all, there were only pluses there). On the other hand, subtraction is not, so minuses must appear only in front of the
b terms, i.e., the coefficients of the subtrahend. Remember that if you want to play it extra safe, you can always turn to Omni's subtracting polynomials calculator for help.
That concludes our swift adventure of algebraic theory. We now change the symbols into numbers (although not all,
x is here to stay) and lay our hands on a nice example.
Example: using the adding and subtracting polynomials calculator
Let's try out both options in the adding and subtracting polynomials calculator, i.e., we'll find both the sum and difference of
P(x) = 4x⁴ - x³ + 5x + 1
Q(x) = x⁵ + 4x⁴ - 7x³ - 3x² + x + 12
First of all, we put our tool to the test. Note how at the top of it, we can choose what we want to find: the sum or the difference by choosing respectively "add" or "subtract" in "I want to ... polynomials."
Next, we need to specify the degrees of
Q(x). We see that the maximal exponents of
x in the two are
5, respectively, so we choose the numbers from the list in corresponding fields. That will trigger formulas for the two polynomials with the notation used underneath:
P(x) = a₄x⁴ + a₃x³ + a₂x² + a₁x + a₀
Q(x) = b₅x⁵ + b₄x⁴ + b₃x³ + b₂x² + b₁x + b₀
Looking back at the two expressions we have, we see that we need to input:
a₄ = 4,
a₃ = -1,
a₂ = 0,
a₁ = 5,
a₀ = 1; and
b₅ = 1,
b₄ = 4,
b₃ = -7,
b₂ = -3,
b₁ = 1,
b₀ = 12.
Take a minute to pay special care of the following things:
b₃are negative because we have minuses in the corresponding places in the polynomials.
- We have
a₀ = 1,
b₅ = 1, and
b₁ = 1even though there are no numbers in the corresponding places in
Q(x). That is because, by convention, if the coefficient is
1, we don't write it. For a similar reason, we have
a₃ = -1with the minus.
- We input
a₂ = 0because
P(x)has no term with
x², which, in fact, means that its coefficient is equal to
The moment we input the last variable, the adding and subtracting polynomials calculator will spit out the answer underneath. However, before we reveal it, let's see how to add and subtract the polynomials ourselves.
We apply the formulas from the above sections. So what is the sum of the polynomials?
P(x) + Q(x) = (4x⁴ - x³ + 5x + 1) + (x⁵ + 4x⁴ - 7x³ - 3x² + x + 12)
= x⁵ + (4 + 4)x⁴ + ((-1) + (-7))x³ - 3x² + (5 + 1)x + (1 + 12)
= x⁵ + 8x⁴ - 8x³ - 3x² + 6x + 13.
We finish by showing how to subtract the two polynomials:
P(x) - Q(x) = (4x⁴ - x³ + 5x + 1) + (x⁵ + 4x⁴ - 7x³ - 3x² + x + 12)
= -x⁵ + (4 - 4)x⁴ + ((-1) - (-7))x³ + 3x² + (5 - 1)x + (1 - 12)
= -x⁵ + 6x³ + 3x² + 4x - 11.
Voilà! It wasn't so bad, was it? Feel free to browse through other Omni tools from the math section and check out what else we can help you with.